0.2x^2+2.1=3.4

Solution for 0.2x^2+2.1=3.4 equation:

0.2x^2+2.1=3.4

We move all terms to the left:

0.2x^2+2.1-(3.4)=0

We add all the numbers together, and all the variables

0.2x^2-1.3=0

a = 0.2; b = 0; c = -1.3;
Δ = b2-4ac
Δ = 02-4·0.2·(-1.3)
Δ = 1.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.04}}{2*0.2}=\frac{0-\sqrt{1.04}}{0.4}
=-\frac{\sqrt{}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.04}}{2*0.2}=\frac{0+\sqrt{1.04}}{0.4}
=\frac{\sqrt{}}{0.4}
$